(a) We know that for one mole of an ideal gas, CV = (∂U/∂T) V Therefore, dU = CV dT For a finite change, ∆U = CV ∆T As for an isothermal process, T is constant so that ∆T = 0. Hence for an isothermal expansion of an ideal gas ∆U=0. (b) We ...

Relation between CP and CV in gaseous systems No external work is being done when a gas is heated at constant volume i.e. gas uses all the haet which is given to it for increasing its internal energy. Hence if temperature of one mole of a ...

Enthalpy of Vaporizations: During evaporation of liquid, some absorption of heat from surroundings takes place. Hence, Liquid evaporation is fulfilled by increase in enthalpy. The increase in enthalpy while evaporation of one mole of water at 25oC is 43.93 kJ. This result can be expressed in the form ...

We know that work differential dw is calculated as: dw= PdV ……………. (1) since volume V is a state function i.e. it is independent of the path [V=f (T,P)] hence dV is an exact differential.Therefore ……. (2) For an ideal gas, we know ...

Let us assume that a system is changing with respect to pressure as well as volume. Let the ‘X’ be the initial state of the system and ‘Y’ is the final state of the system. Now let suppose UX and UY are the energies of ...

Let us suppose that the state of a system changes at constant Pressure. Hence there will be change in volume of the system. Suppose volume changes from V1 to V2 at constant pressure P. Therefore work done w, by the system will be: ...

The energy associated with the disordered, random motion of molecules is called Internal Energy. It is separated in scale from the macroscopic ordered energy associated with moving objects; it refers to the invisible microscopic energy on the atomic and molecular scale. Internal ...

The 1st Law of Thermodynamics tells us that energy is neither created nor destroyed, thus the energy of the universe is a constant. However, energy can certainly be transferred from one part of the universe to another. To work out thermodynamic problems we will need ...