The required equation is
2C + H2 ———-> C2H5
Standard heat of formation i.e. ΔH =?
Writing the thermo-chemical equation of the given data
(i) C2 H2 + 5/2 O2 ————> 2CO2 +
H2 O ΔH = –210.62 kcal (given)
(ii) C + O2 —————-> CO2 ΔH = –84.05 kcal (given)
(iii) H2 + 1/2 O2 ——–> H2O ΔH = –69.32 kcal (given)
Now, multiplying (ii) eq. by 2 and then adding (iii) eq. and subtracting (i) eq. i.e.
i.e. (ii) 2 C + 2 O2 —————-> 2 CO2 ΔH = –168.1 kcal
Hence after adding adding (iii) eq. and subtracting (i) eq. we will get following equation:
2C + H2 —————–> C2 H2 ΔH = 26.80 kcal
Hence, Standard heat of formation of C2 H2 i.e. ΔH = 26.80 kcal.