Give the comparison of work of expansion of an ideal Gas and a van der Waals Gas.

We know that for an ideal gas, work done w is given as:
Wideal = -nRT ln (V2/ V1)
And for a a van der Waals Gas, work done is given as:

ideal Gas and a van der Waals Gas

Hence for the expansion of a gas, V2 > V1, which shows that numerically the work of expansion in the reversible isothermal expansion of an ideal gas is greater than van der Waals Gas.

Category: First Law of Thermodynamics

More Questions

Leave a Reply

Copyright © All rights reserved. TheBigger.com | Privacy Policy | Contact Us | Copyright Policy | Useful Resources