Calculate the pH if 1 mL of 13.6 M HCl is diluted with water to give 1 L of solution.

1 mL of 13.6 M HCl is diluted with water to give 1 L of solution:
Molarity of the diluted solution is given as:

M₁ V₁ = M₂ V₂
13.6 M x 1 mL = M₂ x 1000 mL
Therefore, M₂ = 113.6 / 1000 = 1.36 x 10^-2 M
[H₃O⁺] = 1.36 x 10^-2 M
pH = – log [H₃O⁺] = – log (1.36 x 10^-2)
= – log 1.36 + 2 = – 0.134 + 2 = 1.866
Hence, pH if 1 mL of 13.6 M HCl is diluted with water to give 1 L of solution is equal to 1.866